Webhook receiver Python 3.7

Solution: Webhook receiver Python 3.7

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5.0 (3 ratings)

Last updated 02/2019

Author

Dr. Dragan Jovanovic

Linux Administrator

Description

Who make a Webhook receiver in Python 3?

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Solutions

Peter Dorner

Code: receiver.py

from flask import Flask, request, abort
app = Flask(__name__)
@app.route('/webhook', methods=['POST'])
def webhook():
    if request.method == 'POST':
        print(request.json)
        return '', 200
    else:
        abort(400)
if __name__ == '__main__':
    app.run()

Start up Postman, and do New Request, POST, URL is http://127.0.0.1:5000/webhook, in Body select "raw" and JSON, and put this in: {"id" : "1123"} and his SEND, and the webhook receiver will print {'id': '1123'}.

postman.jpg76

on February 08th, 2019 (8:59 pm)